Hi Ranjitha, thanks for taking the time to make this post! I found it quite useful as I think best in JavaScript and happened to be working on Coin Change (min variant)! I tinkered a bit and came up with very similar code but:

var coinChange = function(coins, amount) {
  if (amount === 0) return 0
  const grid = []
    
  for (let row = 0; row <= coins.length; row++) {
    grid[row] = []
    for (let col = 0; col <= amount; col++) {
      // Prefill zero'th columns with zero, and first row with Infinity
      if (col === 0) {
        grid[row][col] = 0
        continue
      } else if (row === 0) {
        grid[row][col] = Infinity
        continue
      }
      // Tabulation--as we're not on first column or row
      const currCoin = coins[row-1]
      // Current coin larger then column, just pull down last value 
      if (currCoin > col) {
        grid[row][col] = grid[row-1][col]
      } else {
        // Minimum of pulled down last value vs. including coin (1) + previous solution at [col - coin]
        grid[row][col] = Math.min(grid[row-1][col], 1 + grid[row][col - currCoin])
      }
    }   
  }   
  return grid[coins.length][amount] == Infinity ? -1 : grid[coins.length][amount]
};

After having watched a bunch of tabulation youtubes I wanted to make it crystal clear to myself on the meaty part of the solution where we indice based off [current index less the current coin]. Nothing meaningfully different then yours, but I thought you’d like to see that your post inspired some study :) Thanks Ranjitha!